Valid Sudoku
Description
Determine if a 9x9 Sudoku board is valid. Only the filled cells need to be validated according to the following rules:
- Each row must contain the digits
1-9without repetition. - Each column must contain the digits
1-9without repetition. - Each of the 9
3x3sub-boxes of the grid must contain the digits1-9without repetition.
![]()
A partially filled sudoku which is valid.
The Sudoku board could be partially filled, where empty cells are filled with the character '.'.
Example 1:
Input: [ ["5","3",".",".","7",".",".",".","."], ["6",".",".","1","9","5",".",".","."], [".","9","8",".",".",".",".","6","."], ["8",".",".",".","6",".",".",".","3"], ["4",".",".","8",".","3",".",".","1"], ["7",".",".",".","2",".",".",".","6"], [".","6",".",".",".",".","2","8","."], [".",".",".","4","1","9",".",".","5"], [".",".",".",".","8",".",".","7","9"] ] Output: true
Example 2:
Input:
[
["8","3",".",".","7",".",".",".","."],
["6",".",".","1","9","5",".",".","."],
[".","9","8",".",".",".",".","6","."],
["8",".",".",".","6",".",".",".","3"],
["4",".",".","8",".","3",".",".","1"],
["7",".",".",".","2",".",".",".","6"],
[".","6",".",".",".",".","2","8","."],
[".",".",".","4","1","9",".",".","5"],
[".",".",".",".","8",".",".","7","9"]
]
Output: false
Explanation: Same as Example 1, except with the 5 in the top left corner being
modified to 8. Since there are two 8's in the top left 3x3 sub-box, it is invalid.
Note:
- A Sudoku board (partially filled) could be valid but is not necessarily solvable.
- Only the filled cells need to be validated according to the mentioned rules.
- The given board contain only digits
1-9and the character'.'. - The given board size is always
9x9.
Solution(javascript)
/**
* @param {character[][]} board
* @return {boolean}
*/
const isValidSudoku = (board = []) => {
const rows = []
const columns = []
const boxes = []
for (let i = 0; i < board.length; i++) {
for (let j = 0; j < board[i].length; j++) {
const content = board[i][j]
if (content !== '.') {
if (!rows[i]) {
rows[i] = {}
}
if (rows[i][content]) {
return false
}
rows[i][content] = 1
if (!columns[j]) {
columns[j] = {}
}
if (columns[j][content]) {
return false
}
columns[j][content] = 1
const boxNum = Math.floor(i / 3) * 3 + Math.floor(j / 3)
if (!boxes[boxNum]) {
boxes[boxNum] = {}
}
if (boxes[boxNum][content]) {
return false
}
boxes[boxNum][content] = 1
}
}
}
return true
}