Implement Queue using Stacks
Description
Implement the following operations of a queue using stacks.
- push(x) -- Push element x to the back of queue.
- pop() -- Removes the element from in front of queue.
- peek() -- Get the front element.
- empty() -- Return whether the queue is empty.
Example:
MyQueue queue = new MyQueue();queue.push(1); queue.push(2);
queue.peek(); // returns 1 queue.pop(); // returns 1 queue.empty(); // returns false
Notes:
- You must use only standard operations of a stack -- which means only
push to top
,peek/pop from top
,size
, andis empty
operations are valid. - Depending on your language, stack may not be supported natively. You may simulate a stack by using a list or deque (double-ended queue), as long as you use only standard operations of a stack.
- You may assume that all operations are valid (for example, no pop or peek operations will be called on an empty queue).
Solution(javascript)
const Stack = function () {
const stack = []
return {
get length() { return stack.length },
push: x => stack.push(x),
pop: () => stack.pop(),
peek: () => stack[stack.length - 1],
}
}
const MyQueue = function () {
this.s1 = Stack()
this.s2 = Stack()
}
/**
* Push element x to the back of queue.
* @param {number} x
* @return {void}
*/
MyQueue.prototype.push = function (x) {
this.s2.push(x)
}
/**
* Removes the element from in front of queue and returns that element.
* @return {number}
*/
MyQueue.prototype.pop = function () {
if (this.s1.length) {
return this.s1.pop()
}
while (this.s2.length) {
this.s1.push(this.s2.pop())
}
return this.s1.pop()
}
/**
* Get the front element.
* @return {number}
*/
MyQueue.prototype.peek = function () {
if (this.s1.length) {
return this.s1.peek()
}
while (this.s2.length) {
this.s1.push(this.s2.pop())
}
return this.s1.peek()
}
/**
* Returns whether the queue is empty.
* @return {boolean}
*/
MyQueue.prototype.empty = function () {
return this.s1.length === 0 && this.s2.length === 0
}