Maximum Product of Splitted Binary Tree
Description
Given a binary tree root
. Split the binary tree into two subtrees by removing 1 edge such that the product of the sums of the subtrees are maximized.
Since the answer may be too large, return it modulo 10^9 + 7.
Example 1:
Input: root = [1,2,3,4,5,6] Output: 110 Explanation: Remove the red edge and get 2 binary trees with sum 11 and 10. Their product is 110 (11*10)
Example 2:
Input: root = [1,null,2,3,4,null,null,5,6] Output: 90 Explanation: Remove the red edge and get 2 binary trees with sum 15 and 6.Their product is 90 (15*6)
Example 3:
Input: root = [2,3,9,10,7,8,6,5,4,11,1] Output: 1025
Example 4:
Input: root = [1,1] Output: 1
Constraints:
- Each tree has at most
50000
nodes and at least2
nodes. - Each node's value is between
[1, 10000]
.
Solution(javascript)
/**
* Definition for a binary tree node.
* function TreeNode(val) {
* this.val = val;
* this.left = this.right = null;
* }
*/
/** 1. In-order traverse + Prefix Sum(中序遍历顺序不对,行不通)
* 2. 记录每个节点的 sum, 用根节点的 sum 减去对应的节点
* @param {TreeNode} root
* @return {number}
*/
const maxProduct = function (root) {
let max = 0
let total = 0
const sum = (node) => {
if (!node) {
return 0
}
const leftSum = sum(node.left)
const rightSum = sum(node.right)
const currentSum = leftSum + rightSum + node.val
max = Math.max(
max, (total - leftSum) * leftSum, (total - rightSum) * rightSum,
)
return currentSum
}
total = sum(root)
sum(root)
return (max % (10 ** 9 + 7))
}